MODUL 2
1.Buatlah rangkaian logika dan tabel kebenaran untuk persamaan-persamaan berikut :
1.Buatlah rangkaian logika dan tabel kebenaran untuk persamaan-persamaan berikut :
- S = B (A+C) + AC + D
- Q = (( ~((~(~A + B) ^ (B^C)) + (~B^C))
SOAL 1
A. S = B(A+C) + A.C + D
TABEL KEBENARAN
A. S = B(A+C) + A.C + D
TABEL KEBENARAN
A
|
B
|
C
|
D
|
A+C
|
B(A+C)
|
A.C
|
B(A+C)
+ A.C
|
S
= B(A+C) + A.C + D
|
1
|
1
|
1
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1
|
1
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1
|
1
|
1
|
1
|
1
|
1
|
1
|
0
|
1
|
1
|
1
|
1
|
1
|
1
|
1
|
0
|
1
|
1
|
1
|
0
|
1
|
1
|
1
|
1
|
0
|
0
|
1
|
1
|
0
|
1
|
1
|
1
|
0
|
1
|
1
|
1
|
0
|
1
|
1
|
1
|
1
|
0
|
1
|
0
|
1
|
0
|
1
|
1
|
1
|
1
|
0
|
0
|
1
|
1
|
0
|
0
|
0
|
1
|
1
|
0
|
0
|
0
|
1
|
0
|
0
|
0
|
0
|
0
|
1
|
1
|
1
|
1
|
1
|
0
|
1
|
1
|
0
|
1
|
1
|
0
|
1
|
1
|
0
|
1
|
1
|
0
|
1
|
0
|
1
|
0
|
0
|
0
|
0
|
1
|
0
|
1
|
0
|
0
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0
|
0
|
0
|
0
|
0
|
0
|
0
|
1
|
1
|
1
|
0
|
0
|
0
|
1
|
0
|
0
|
1
|
0
|
1
|
0
|
0
|
0
|
0
|
0
|
0
|
0
|
1
|
0
|
0
|
0
|
0
|
1
|
0
|
0
|
0
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0
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0
|
0
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0
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0
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0
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SWITCH
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KONDISI
LED
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|||
A
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B
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C
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D
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|
ON
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ON
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ON
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ON
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NYALA
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ON
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ON
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ON
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OFF
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NYALA
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ON
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ON
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OFF
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ON
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NYALA
|
ON
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ON
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OFF
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OFF
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NYALA
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ON
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OFF
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ON
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ON
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NYALA
|
ON
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OFF
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ON
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OFF
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NYALA
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ON
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OFF
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OFF
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ON
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NYALA
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ON
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OFF
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OFF
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OFF
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MATI
|
OFF
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ON
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ON
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ON
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NYALA
|
OFF
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ON
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ON
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OFF
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NYALA
|
OFF
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ON
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OFF
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ON
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NYALA
|
OFF
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ON
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OFF
|
OFF
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MATI
|
OFF
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OFF
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ON
|
ON
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NYALA
|
OFF
|
OFF
|
ON
|
OFF
|
MATI
|
OFF
|
OFF
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OFF
|
ON
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NYALA
|
OFF
|
OFF
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OFF
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OFF
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MATI
|
B. X = ⌐(⌐(⌐A+B)).(B.C))+
⌐B.C
A
|
B
|
C
|
⌐A
|
⌐B
|
⌐A+B
|
⌐(⌐A+B)
|
B.C
|
(⌐(⌐A+B)).(B.C)
|
⌐(⌐(⌐A+B)).(B.C))
|
⌐B.C
|
X = ⌐(⌐(⌐A+B)).(B.C))+ ⌐B.C
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1
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1
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1
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0
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0
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1
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0
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1
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0
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1
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0
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1
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1
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1
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0
|
0
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0
|
1
|
0
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0
|
0
|
1
|
0
|
1
|
1
|
0
|
1
|
0
|
1
|
0
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1
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0
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0
|
1
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1
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1
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1
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0
|
0
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0
|
1
|
0
|
1
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0
|
0
|
1
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0
|
1
|
0
|
1
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1
|
1
|
0
|
1
|
0
|
1
|
0
|
1
|
0
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1
|
0
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1
|
0
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1
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0
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1
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0
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0
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0
|
1
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0
|
1
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0
|
0
|
1
|
1
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1
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1
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0
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0
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0
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1
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1
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1
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0
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0
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0
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1
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1
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1
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0
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0
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0
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1
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0
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1
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SWITCH
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KONDISI
LED
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||
A
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B
|
C
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ON
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ON
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ON
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NYALA
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ON
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ON
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OFF
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NYALA
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ON
|
OFF
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ON
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NYALA
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ON
|
OFF
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OFF
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NYALA
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OFF
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ON
|
ON
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NYALA
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OFF
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ON
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OFF
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NYALA
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OFF
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OFF
|
ON
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NYALA
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OFF
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OFF
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OFF
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NYALA
|
SOAL 2
Dari rangkaian-rangkaian berikut ini, bandingkan rangkaian mana saja yang mempunyai fungsi yang sama. Buktikan dengan menggunakan Tabel Kebenaran.
Dari rangkaian-rangkaian berikut ini, bandingkan rangkaian mana saja yang mempunyai fungsi yang sama. Buktikan dengan menggunakan Tabel Kebenaran.
I.
(A+⌐B).(B+C).B
A
|
B
|
C
|
⌐B
|
(A+⌐B)
|
(B+C)
|
(A+⌐B).(B+C)
|
(A+⌐B).(B+C).B
|
1
|
1
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1
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0
|
1
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1
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1
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1
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1
|
1
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0
|
0
|
1
|
1
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1
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1
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1
|
0
|
1
|
1
|
1
|
1
|
1
|
0
|
1
|
0
|
0
|
1
|
1
|
0
|
0
|
0
|
0
|
1
|
1
|
0
|
0
|
1
|
0
|
0
|
0
|
1
|
0
|
0
|
0
|
1
|
0
|
0
|
0
|
0
|
1
|
1
|
1
|
1
|
0
|
0
|
0
|
0
|
0
|
1
|
1
|
0
|
0
|
0
|
SWITCH
|
KONDISI
LED
|
||
A
|
B
|
C
|
|
ON
|
ON
|
ON
|
NYALA
|
ON
|
ON
|
OFF
|
NYALA
|
ON
|
OFF
|
ON
|
MATI
|
ON
|
OFF
|
OFF
|
MATI
|
OFF
|
ON
|
ON
|
MATI
|
OFF
|
ON
|
OFF
|
MATI
|
OFF
|
OFF
|
ON
|
MATI
|
OFF
|
OFF
|
OFF
|
MATI
|
II.
⌐(⌐(S.T).(T+S))
S
|
T
|
S.T
|
⌐(S.T)
|
T+S
|
⌐(S.T).(T+S)
|
⌐(⌐(S.T).(T+S))
|
1
|
1
|
1
|
0
|
1
|
0
|
1
|
1
|
0
|
0
|
1
|
1
|
1
|
0
|
0
|
1
|
0
|
1
|
1
|
1
|
0
|
0
|
0
|
0
|
1
|
0
|
0
|
1
|
SWITCH
|
LED
|
|
S
|
T
|
|
ON
|
ON
|
NYALA
|
ON
|
OFF
|
MATI
|
OFF
|
ON
|
MATI
|
OFF
|
OFF
|
NYALA
|
III.
(U.V)+(⌐V.W)
U
|
V
|
W
|
U.V
|
⌐V
|
⌐V.W
|
(U.V)+(⌐V.W)
|
1
|
1
|
1
|
1
|
0
|
0
|
1
|
1
|
1
|
0
|
1
|
0
|
0
|
1
|
1
|
0
|
1
|
0
|
1
|
1
|
1
|
1
|
0
|
0
|
0
|
1
|
0
|
0
|
0
|
1
|
1
|
0
|
0
|
0
|
0
|
0
|
1
|
0
|
0
|
0
|
0
|
0
|
0
|
0
|
1
|
0
|
1
|
1
|
1
|
0
|
0
|
0
|
0
|
1
|
0
|
0
|
SWITCH
|
KONDISI
LED
|
||
U
|
V
|
W
|
|
ON
|
ON
|
ON
|
NYALA
|
ON
|
ON
|
OFF
|
NYALA
|
ON
|
OFF
|
ON
|
NYALA
|
ON
|
OFF
|
OFF
|
MATI
|
OFF
|
ON
|
ON
|
MATI
|
OFF
|
ON
|
OFF
|
MATI
|
OFF
|
OFF
|
ON
|
NYALA
|
OFF
|
OFF
|
OFF
|
MATI
|
IV.
(P.Q)+
⌐(Q+P)
P
|
Q
|
P.Q
|
Q+P
|
⌐(Q+P)
|
(P.Q)+⌐(Q+P)
|
1
|
1
|
1
|
1
|
0
|
1
|
1
|
0
|
0
|
1
|
0
|
0
|
0
|
1
|
0
|
1
|
0
|
0
|
0
|
0
|
0
|
0
|
1
|
1
|
SWITCH
|
LED
|
|
P
|
Q
|
|
ON
|
ON
|
NYALA
|
ON
|
OFF
|
MATI
|
OFF
|
ON
|
MATI
|
OFF
|
OFF
|
NYALA
|
SCREEN SHOOT Soal 1
Screen Shoot Soal 2
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